V2AS
问路
意见反馈
↓ 按住下拉
(洛谷P4213)杜教筛
https://www.cnblogs.com/Mychael/p/8744633.html pragma GCC optimize(3, "Ofast", "inline") include <bits/stdc++.h> define start ios::sync_with_std ......
int
sum
mu
phi
maxn
bugku_EasyMath
bugku_EasyMath 简单的数学题 from Crypto.Util.number import getPrime, bytes_to_long from secret import flag p = getPrime(2048) q = getPrime(2048) x = ......
mod
import
gmpy2
adsbygoogle
getPrime
论文解读(MetaAdapt)《MetaAdapt: Domain Adaptive Few-Shot Misinformation Detection via Meta Learning》
Note:[ wechat:Y466551 | 可加勿骚扰,付费咨询 ] 论文信息 论文标题:MetaAdapt: Domain Adaptive Few-Shot Misinformation Detection via Meta Learning论文作者 ......
boldsymbol
论文
theta
Graph
quad
【了解LLM】——LoRA
本文地址:https://www.cnblogs.com/wanger-sjtu/p/17470327.html 论文链接:link code: github LoRA,英文全称Low-Rank Adaptation of Large Language Models,直 ......
LoRa
Phi
LoRA
Delta
参数
论文翻译:2021_Real-Time Denoising and Dereverberation wtih Tiny Recurrent U-Net
论文地址:微型循环U-Net实时降噪和去混响 论文代码: https://github.com/YangangCao/TRUNet https://github.com/amirpashamobinitehrani/tinyrecurrentunet 引用 ......
Net
模型
掩码
混响
Proc
论文解读(CBL)《CNN-Based Broad Learning for Cross-Domain Emotion Classification》
Note:[ wechat:Y466551 | 付费咨询,非诚勿扰 ] 论文信息 论文标题:CNN-Based Broad Learning for Cross-Domain Emotion Classification论文作者:Rong Zeng, Hong ......
boldsymbol
left
right
mathrm
text
论文解读(ECACL)《ECACL: A Holistic Framework for Semi-Supervised Domain Adaptation》
Note:[ wechat:Y466551 | 付费咨询,非诚勿扰 ] 论文信息 论文标题:ECACL: A Holistic Framework for Semi-Supervised Domain Adaptation论文作者:Kai Li, Chang ......
left
right
mathbf
论文
quad
曲线艺术编程 coding curves 第十二章 超级椭圆与超级方程(Superellipses and Superformulas)
第十三章 超级椭圆与超级方程(Superellipses and Superformulas) 原作:Keith Peters https://www.bit-101.com/blog/2022/11/coding-curves/ 译者:池中物王二狗(s ......
超级
椭圆
编程
n2
pow
DASCTF 2023 & 0X401七月暑期挑战赛
比赛只出了一道,小菜不是罪过-_- controlflow 这个题动调到底就行 for i in range(40): after_xor[i]=inp[i]^0x401 after_xor[i] += i * i; for i in ra ......
x0
enc
x48
x45
x8b
容斥原理——hdu2841
记得要开ll /* 莫比乌斯反演模板题,也可以直接算
phi
来做 容斥的解法 求x[1..m],在[1,n]中和其互质的数的个数即可 那么就是n-和x不互质的数个数即可 */ include ......
容斥
int
fac
原理
num
V2AS = Way To Ask
V2AS 一个技术分享与创造的静土
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