这是我依据这篇博文http://hi.baidu.com/wsapyoemdfacmqr/item/bdfb5c0a74c904d01ef0466d。来在cocos2dx上编写。这是终于的效果图：

红色的地方是执行轨迹，黑色是禁止区域，接下来是代码，请结合那篇博文观看：

首先创建地板类，必需要有x和y，还有依据那篇博文的h和g。这是h文件里的代码：

#include "cocos2d.h"

typedef enum _FloorState

{

    FloorGround,

    FloorRiver

} FloorState;

class Floor : public cocos2d::LayerColor

{

public:

    Floor();

    ~Floor(){}

    

    static int at(int x, int y);

    static Floor * create(const cocos2d::Color4B& color);

    bool initWithColor(const cocos2d::Color4B& color);

    

    int getF();

    

private:

    CC_SYNTHESIZE(int, _x, X);

    CC_SYNTHESIZE(int, _y, Y);

    

    CC_SYNTHESIZE(int, _h, H);

    CC_SYNTHESIZE(int, _g, G);

    

    CC_SYNTHESIZE(FloorState, _landForm, LandForm);

    

    CC_SYNTHESIZE(Floor *, _lastFloor, LastFloor);

};

基本上没有什么难度，另外，那个静态方法at使用了从数组中高速获取地板。

然后是cpp文件：

#include "Floor.h"

USING_NS_CC;

Floor::Floor()

{

    _x = 0;

    _y = 0;

    

    _h = -1;

    _g = -1;

    

    _lastFloor = NULL;

}

int Floor::at(int x, int y)

{

    return x + 28 * y;

}

Floor *Floor::create(const cocos2d::Color4B &color)

{

    Floor *_floor = new Floor();

    if ( _floor && _floor -> initWithColor( color ) )

    {

        _floor -> autorelease();

        return _floor;

    }

    

    delete _floor;

    _floor = NULL;

    return NULL;

}

bool Floor::initWithColor(const cocos2d::Color4B &color)

{

    if ( LayerColor::initWithColor(color, 39, 39) )

    {

        return true;

    }

    

    return false;

}

int Floor::getF()

{

    return _h + _g;

}

然后在执行的Layer中：

void MainScene::createGround()

{

    for (int y = 0; y < 18; y++)

    {

        for (int x = 0; x < 28; x++)

        {

            auto _floor = Floor::create( Color4B(255, 255, 255, 255) );

            _floor -> setPosition(x * (_floor -> getContentSize().width + 1), y * (_floor -> getContentSize().height + 1));

            _floor -> setX(x);

            _floor -> setY(y);

            _floor -> setLandForm( FloorGround );

            this -> addChild( _floor );

            

            if ( (x == 15 && y < 7) || (x == 3 && y < 10) || (y == 12 && x < 20) || (x == 5 && y > 8) || (x == 13 && y > 1) )

            {

                _floor -> setColor( Color3B(0, 0, 0) );

                _floor -> setLandForm( FloorRiver );

            }

            ground.pushBack( _floor );

        }

    }

}

当中，这种方法：_floor -> setLandForm( FloorRiver )使用来制造禁止区域

然后加入起点和终点：

end = Floor::create( Color4B(0, 255, 255, 10) );

    end -> setPosition( (ground.at( Floor::at(24, 14) )) -> getPosition() );

    end -> setX(24);

    end -> setY(14);

    this -> addChild( end );

    

    origin = Floor::create( Color4B(255, 255, 0, 255) );

    origin -> setPosition( (ground.at( Floor::at(0, 0) )) -> getPosition() );

    origin -> setX(0);

    origin -> setY(0);

    origin -> setH( fabs((end -> getX() - origin -> getX())) + fabs( end -> getY() - origin -> getY() ) );

    origin -> setG(0);

    this -> addChild( origin );

    open.pushBack( origin );

在这些完毕后，就是须要使用A*算法来计算出路径了

首先从open数组中寻找F最小的地板；之后。将上下左右的地板做个推断，是否增加数组中。这部分放在一个死循环中，当增加的地板正是终点时，能够结束：

while (1)

    {

        Vector< Floor * >::iterator index = open.begin();

        Vector< Floor * >::iterator minF = index;

        for (; index != open.end(); index++)

        {

            if ( (*index) -> getF() < (*minF) -> getF() )

            {

                minF = index;

            }

        }

        

        Floor *_origin = (*minF);

        

        handleFloor(_origin, _origin -> getX(), _origin -> getY() - 1);

        handleFloor(_origin, _origin -> getX(), _origin -> getY() + 1);

        handleFloor(_origin, _origin -> getX() - 1, _origin -> getY());

        handleFloor(_origin, _origin -> getX() + 1, _origin -> getY());

        

        open.eraseObject( _origin );

        close.pushBack( _origin );

        _origin -> setColor( Color3B(0, 255, 0) );

        

        Floor *getEnd = open.at( open.size() - 1 );

        if ( getEnd -> getX() == end -> getX() && getEnd -> getY() == end -> getY() )

        {

            CCLOG("ENDG");

            return;

        }

    }

handleFloor函数是用来推断该地板是否可以增加数组中

void MainScene::handleFloor(Floor *_floor, int x, int y)

{

    if ( x < 0 || y < 0 )

    {

        return;

    }

    Floor *handle = ground.at( Floor::at(x, y) );

    handle -> setX(x);

    handle -> setY(y);

    handle -> setH( fabs((end -> getX() - handle -> getX())) + fabs( end -> getY() - handle -> getY() ) );

    handle -> setG( fabs((origin -> getX() - handle -> getX())) + fabs( origin -> getY() - handle -> getY() ) );

    JUDGE( handle, _floor );

}

#define JUDGE(__FLOOR__, __LAST__)    \

if ( !open.contains(__FLOOR__) && !close.contains(__FLOOR__) && __FLOOR__ -> getLandForm() != FloorRiver )  \

{ \

open.pushBack( __FLOOR__ ); \

__FLOOR__ -> setColor( Color3B(100, 100, 100) ); \

__FLOOR__ -> setLastFloor( __LAST__ );  \

}   \

之后，就是取出open数组终的最后一块地板，并能够获取这块地板的上一块地板。并将其颜色改变

Floor *index = open.at( open.size() - 1 );

    

    while ( index -> getLastFloor() != NULL )

    {

        index -> setColor( Color3B(255, 0, 0) );

        index = index -> getLastFloor();

    }

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