mysql学习教程参考：https://www.w3school.com.cn/sql/index.asp

where 与 having实例运用参考：https://www.2cto.com/database/201712/706595.html

--可选认证中至少有一项通过的用户占比，直接计算
select
 count(distinct case when c.auth_type='可选' and c.auth_status in ('已认证', '已过期') then c.user_id end) as pass_cnt
,count(distinct c.user_id) as tot_cnt
,count(distinct case when c.auth_type='可选' and c.auth_status in ('已认证', '已过期') then c.user_id end)/count(distinct c.user_id) per_cnt
from(

 select a.*,ath.auth_item,ath.auth_type,ath.auth_status,ath.auth_suc_time
  from(
   select laf.user_id,laf.main_order_id,laf.loan_apply_submit_time
   from pl_performance_loan_apply_fact laf
   left join pl_customer_basic_info usb on laf.user_id=usb.user_id
   where laf.reborrow_status = '首借' and usb.merchant_no='DuitSayang'
      and date(laf.loan_apply_submit_time)>='2019-08-03' and date(laf.loan_apply_submit_time)<='2019-08-05'
) a
left join pl_customer_auth_info ath on a.user_id = ath.user_id

) c
;

--找出未通过认证的用户，巧用group by,having 
select a.user_id,a.phone
  from(
   select laf.user_id,laf.main_order_id,laf.loan_apply_submit_time,usb.phone
   from pl_performance_loan_apply_fact laf
   left join pl_customer_basic_info usb on laf.user_id=usb.user_id
   where laf.reborrow_status = '首借' and usb.merchant_no='DuitSayang'
      and date(laf.loan_apply_submit_time)>='2019-08-03' and date(laf.loan_apply_submit_time)<='2019-08-05'
) a
left join pl_customer_auth_info ath on a.user_id = ath.user_id
group by a.user_id,a.phone
having max( case when ath.auth_type='可选' and ath.auth_status in ('已认证', '已过期') then 1 else 0 end) = 0

--注册未申请的phone

# 9月注册未申贷用户电话号码

select concat('\'',usb.phone) as phone
from (
select phone, user_id from pl_customer_basic_info
where substr(regist_time,1,7)='2019-09'
) usb
left join pl_performance_loan_apply_fact laf on usb.user_id=laf.user_id
group by usb.phone
having max(case when laf.user_id is not null then 1 else 0 end) = 0
;