我觉得这一系列的标题应该是:PERL,从入门到放弃
USE IT OR U WILL LOSE IT
参考资料:
https://qntm.org/files/perl/perl.html
在线perl编译器:
https://www.tutorialspoint.com/execute_perl_online.php
use strict;
use warnings;
my $num = 12.34;
my $str = "hello, "."m'lady";
print $str."\n";
my @arr = (1, "hi", 3,);
print $arr[0]."\n";
print "$arr[-2]\n";
print "Hello \$str \@arr"
啦啦啦今天继续啊
数组长度:
my @arr = (2, "Hi", "my", "lady", "!");
print scalar @arr;
print "\n";
print $#arr;
use strict;
use warnings;
my %hashTable = ("1st" => "hi",
"2nd" => "my",
"3rd" => "lady");
print $hashTable{"1st"};
use strict;
use warnings;
my %hashTable = (1=>"hi", 2=>"my", "3rd"=>"lady");
my @arr = %hashTable;
print @arr;
print $arr[0];
#print $hashTable{1};
#print $hashTable{"1"};
列表指的是用()构建的东西,array和hash都是。列表可以作为一个元素放在列表中间,但是会失去层次结构。hash的话,
use strict;
use warnings;
my @array = (
"apples",
"bananas",
(
"inner",
"list",
"several",
"entries",
),
"cherries",
);
my $i = 0;
while ($i <= $#array) {
print "array[$i] is ".$array[$i]."\n";
$i = $i + 1;
}
但其实list与array还是不同的,如下例:
my @arr = ("alpha", "beta", "gamma", "pie");
my $num = @arr;
print "$num\n";
my $num1 = ("alpha", "beta", "gamma", "pie");
print "$num1\n";
Every expression in Perl is evaluated either in scalar context or list context
而对很多函数来说,对scalar和list的处理方式是不同的,如reverse:
# link. no reverse
print reverse "hello, my lady", 3, " ";
print "\n";
my $scalar = reverse "hello, my lady";
print "$scalar\n";
可以在前面强制加scalar,让函数可以按照scalar的方式处理:
print scalar reverse "hello world"; # "dlrow olleh"
而在下面的例子中,给$outer[3]赋值时,由于它是scalar,所以取得的值只能是数组长度,而非数组。
my @outer = ("Sun", "Mercury", "Venus", undef, "Mars");
my @inner = ("Earth", "Moon");
$outer[3] = @inner;
print $outer[3]; # "2"
好吧,为了解决这个问题,使用引用:
my $colour = "Indigo";
my $scalarRef = \$colour;
print $colour; # "Indigo"
print $scalarRef; # e.g. "SCALAR(0x182c180)"
print ${ $scalarRef }; # "Indigo"
print $$scalarRef;
my @colours = ("Red", "Orange", "Yellow", "Green", "Blue");
my $arrayRef = \@colours;
print $colours[0]; # direct array access
print ${ $arrayRef }[0]; # use the reference to get to the array
print $arrayRef->[0]; # exactly the same thing
my %atomicWeights = ("Hydrogen" => 1.008, "Helium" => 4.003, "Manganese" => 54.94);
my $hashRef = \%atomicWeights;
print $atomicWeights{"Helium"}; # direct hash access
print ${ $hashRef }{"Helium"}; # use a reference to get to the hash
print $hashRef->{"Helium"}; # exactly the same thing - this is very common
我们希望定义自己的数据类型,类似C++里类的概念,所以我们这样做:
# Braces denote an anonymous hash
my $owner1Ref = {
"name" => "Santa Claus",
"DOB" => "1882-12-25",
};
my $owner2Ref = {
"name" => "Mickey Mouse",
"DOB" => "1928-11-18",
};
my $ownersRef = [ $owner1Ref, $owner2Ref ];
my %account = (
"number" => "12345678",
"opened" => "2000-01-01",
"owners" => $ownersRef,
);
注意,这里$owner1Ref和$owner2Ref存的其实是一个匿名hash的引用,$ownersRef存的则是匿名array的引用。既然时候引用,
它们的实际值就是地址。所以%account中才能够保存完整的信息。等价于:
my %account = (
"number" => "31415926",
"opened" => "3000-01-01",
"owners" => [
{
"name" => "Philip Fry",
"DOB" => "1974-08-06",
},
{
"name" => "Hubert Farnsworth",
"DOB" => "2841-04-09",
},
],
);
如何打印?使用->
print "Account #", $account{"number"}, "\n";
print "Opened on ", $account{"opened"}, "\n";
print "Joint owners:\n";
print "\t", $account{"owners"}->[0]->{"name"}, " (born ", $account{"owners"}->[0]->{"DOB"}, ")\n";
print "\t", $account{"owners"}->[1]->{"name"}, " (born ", $account{"owners"}->[1]->{"DOB"}, ")\n";
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