拿到程序先进行查壳,避免做过多无用功
确认是无壳,32位可执行文件,直接将其拖入到IDAPro中
直接f5大法,分析伪代码
int __cdecl main_0(int argc, const char **argv, const char **envp)
{
size_t v3; // eax
const char *v4; // eax
size_t v5; // eax
char v7; // [esp+0h] [ebp-188h]
char v8; // [esp+0h] [ebp-188h]
signed int j; // [esp+DCh] [ebp-ACh]
int i; // [esp+E8h] [ebp-A0h]
signed int v11; // [esp+E8h] [ebp-A0h]
char Destination[108]; // [esp+F4h] [ebp-94h] BYREF
char Str[28]; // [esp+160h] [ebp-28h] BYREF
char v14[8]; // [esp+17Ch] [ebp-Ch] BYREF
for ( i = 0; i < 100; ++i ) //貌似是初始化空间
{
if ( (unsigned int)i >= 0x64 )
j____report_rangecheckfailure();
Destination[i] = 0;
}
sub_41132F("please enter the flag:", v7);
sub_411375("%20s", (char)Str);
v3 = j_strlen(Str); //v3->Str的长度
v4 = (const char *)sub_4110BE(Str, v3, v14);
strncpy(Destination, v4, 0x28u); //将v4的前0x28个字符复制到Destination
v11 = j_strlen(Destination); //v11-》des的长度
for ( j = 0; j < v11; ++j ) //des每个字符+i
Destination[j] += j;
v5 = j_strlen(Destination); //v5-》des的长度
if ( !strncmp(Destination, Str2, v5) ) //就是将des和Str2进行比较
sub_41132F("rigth flag!\n", v8);
else
sub_41132F("wrong flag!\n", v8);
return 0;
}
分析文件执行流向
读取字符串-》进行sub_4110BE()加密处理=》再将加密后的字符串的每个字符按顺序加所在顺序索引=》最后再将该字符串和Str2进行比较就可以了
sub_4110BE()是一个处理函数,跟进去看
void *__cdecl sub_411AB0(char *a1, unsigned int a2, int *a3)
{
int v4; // [esp+D4h] [ebp-38h]
int v5; // [esp+D4h] [ebp-38h]
int v6; // [esp+D4h] [ebp-38h]
int v7; // [esp+D4h] [ebp-38h]
int i; // [esp+E0h] [ebp-2Ch]
unsigned int v9; // [esp+ECh] [ebp-20h]
int v10; // [esp+ECh] [ebp-20h]
int v11; // [esp+ECh] [ebp-20h]
void *v12; // [esp+F8h] [ebp-14h]
char *v13; // [esp+104h] [ebp-8h]
if ( !a1 || !a2 )
return 0;
v9 = a2 / 3;
if ( (int)(a2 / 3) % 3 )
++v9;
v10 = 4 * v9;
*a3 = v10;
v12 = malloc(v10 + 1);
if ( !v12 )
return 0;
j_memset(v12, 0, v10 + 1);
v13 = a1;
v11 = a2;
v4 = 0;
while ( v11 > 0 )
{
byte_41A144[2] = 0;
byte_41A144[1] = 0;
byte_41A144[0] = 0;
for ( i = 0; i < 3 && v11 >= 1; ++i )
{
byte_41A144[i] = *v13;
--v11;
++v13;
}
if ( !i )
break;
switch ( i )
{
case 1:
*((_BYTE *)v12 + v4) = aAbcdefghijklmn[(int)(unsigned __int8)byte_41A144[0] >> 2];
v5 = v4 + 1;
*((_BYTE *)v12 + v5) = aAbcdefghijklmn[((byte_41A144[1] & 0xF0) >> 4) | (16 * (byte_41A144[0] & 3))];
*((_BYTE *)v12 + ++v5) = aAbcdefghijklmn[64];
*((_BYTE *)v12 + ++v5) = aAbcdefghijklmn[64];
v4 = v5 + 1;
break;
case 2:
*((_BYTE *)v12 + v4) = aAbcdefghijklmn[(int)(unsigned __int8)byte_41A144[0] >> 2];
v6 = v4 + 1;
*((_BYTE *)v12 + v6) = aAbcdefghijklmn[((byte_41A144[1] & 0xF0) >> 4) | (16 * (byte_41A144[0] & 3))];
*((_BYTE *)v12 + ++v6) = aAbcdefghijklmn[((byte_41A144[2] & 0xC0) >> 6) | (4 * (byte_41A144[1] & 0xF))];
*((_BYTE *)v12 + ++v6) = aAbcdefghijklmn[64];
v4 = v6 + 1;
break;
case 3:
*((_BYTE *)v12 + v4) = aAbcdefghijklmn[(int)(unsigned __int8)byte_41A144[0] >> 2];
v7 = v4 + 1;
*((_BYTE *)v12 + v7) = aAbcdefghijklmn[((byte_41A144[1] & 0xF0) >> 4) | (16 * (byte_41A144[0] & 3))];
*((_BYTE *)v12 + ++v7) = aAbcdefghijklmn[((byte_41A144[2] & 0xC0) >> 6) | (4 * (byte_41A144[1] & 0xF))];
*((_BYTE *)v12 + ++v7) = aAbcdefghijklmn[byte_41A144[2] & 0x3F];
v4 = v7 + 1;
break;
}
}
*((_BYTE *)v12 + v4) = 0;
return v12;
}
这里我也是看wp的,才知道是个base64加密,还得积累
-点击Str2,进行查看,得到一个字符串
逆向分析
将字符串按顺序减掉数组索引,再进行base64解密,即可得到flag
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