记一次 .NET 某旅行社审批系统 崩溃分析
阅读原文时间:2023年08月21日阅读:5

1. 讲故事

前些天有位朋友找到我,说他的程序跑着跑着就崩溃了,让我看下怎么回事,其实没怎么回事,抓它的 crash dump 就好,具体怎么抓也是被问到的一个高频问题,这里再补一下链接: [.NET程序崩溃了怎么抓 Dump ? 我总结了三种方案] https://www.cnblogs.com/huangxincheng/p/14811953.html ,采用第二种 AEDebug 的形式抓取即可。

1. 崩溃原因是什么

如果dump中塞了异常,用 windbg 打开的时候会有一个提示 This dump file has an exception of interest stored in it,输出如下:

************* Path validation summary **************
Response                         Time (ms)     Location
Deferred                                       SRV*C:\mysymbols*http://msdl.microsoft.com/download/symbols
Symbol search path is: SRV*C:\mysymbols*http://msdl.microsoft.com/download/symbols
Executable search path is:
Windows 7 Version 7601 (Service Pack 1) MP (4 procs) Free x64
Product: Server, suite: Enterprise TerminalServer SingleUserTS
Debug session time: Wed Jun 14 13:34:49.000 2023 (UTC + 8:00)
System Uptime: 0 days 3:28:04.223
Process Uptime: 0 days 0:00:14.000
................................................................
................................................................
......................................................
This dump file has an exception of interest stored in it.
The stored exception information can be accessed via .ecxr.
(9e4.bc4): Stack overflow - code c00000fd (first/second chance not available)
For analysis of this file, run !analyze -v
clr!SlowAllocateString+0x11:
000007fe`f9236451 48c785b0fffffffeffffff mov qword ptr [rbp-50h],0FFFFFFFFFFFFFFFEh ss:00000000`123d5fd0=0000000000000000复制

从卦中看当前有一个 Stack overflow - code c00000fd 异常,说实话好久都没看到 栈溢出 了,甚是想念,既然说栈溢出了,那就看下异常前是个啥情况,使用 .excr 即可。

0:028> .excr;k
rax=00000000123d6048 rbx=00000000123d5d70 rcx=0000000000000001
rdx=0000000000000001 rsi=0000000000000000 rdi=00000000123d5880
rip=000007fef9236451 rsp=00000000123d5fb0 rbp=00000000123d6020
 r8=00000000ffffffff  r9=0000000000000000 r10=00000000123d618e
r11=0000000000000000 r12=0000000000000000 r13=0000000000000000
r14=0000000000000000 r15=0000000000000001
iopl=0         nv up ei pl nz na pe nc
cs=0033  ss=002b  ds=002b  es=002b  fs=0053  gs=002b             efl=00010200
clr!SlowAllocateString+0x11:
000007fe`f9236451 48c785b0fffffffeffffff mov qword ptr [rbp-50h],0FFFFFFFFFFFFFFFEh ss:00000000`123d5fd0=0000000000000000
  *** Stack trace for last set context - .thread/.cxr resets it
 # Child-SP          RetAddr               Call Site
00 00000000`123d5fb0 000007fe`f920a5bd     clr!SlowAllocateString+0x11
01 00000000`123d6050 000007fe`f920a9c7     clr!StringObject::NewString+0x25
02 00000000`123d6080 000007fe`f920a80d     clr!Int32ToDecStr+0xdf
03 00000000`123d6320 000007fe`9ab3bb72     clr!COMNumber::FormatInt32+0x10d
04 00000000`123d65f0 000007fe`9ab33e04     0x000007fe`9ab3bb72
05 00000000`123d6630 000007fe`9ab3be52     0x000007fe`9ab33e04
06 00000000`123d6720 000007fe`9ab3bd2a     0x000007fe`9ab3be52
07 00000000`123d6790 000007fe`9ab33e35     0x000007fe`9ab3bd2a
08 00000000`123d67f0 000007fe`9ab3be52     0x000007fe`9ab33e35
09 00000000`123d68e0 000007fe`9ab3bd2a     0x000007fe`9ab3be52
...
ff 00000000`123df860 000007fe`9ab3bd2a     0x000007fe`9ab3be52复制

从卦中看,当前默认的 255 个栈帧全部被打满,看样子是无限死循环了,为了能看到托管部分我们改用 !clrstack 命令。

0:028> !clrstack
OS Thread Id: 0xbc4 (28)
        Child SP               IP Call Site
00000000123d63b8 000007fef9236451 [HelperMethodFrame_PROTECTOBJ: 00000000123d63b8] System.Number.FormatInt32(Int32, System.String, System.Globalization.NumberFormatInfo)
00000000123d65f0 000007fe9ab3bb72 pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Byte[])
00000000123d6630 000007fe9ab33e04 pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Byte[], Int64, Int64, Boolean)
00000000123d6720 000007fe9ab3be52 pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Int32, Int32)
00000000123d6790 000007fe9ab3bd2a pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Byte[], Boolean)
00000000123d67f0 000007fe9ab33e35 pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Byte[], Int64, Int64, Boolean)
00000000123d68e0 000007fe9ab3be52 pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Int32, Int32)
00000000123d6950 000007fe9ab3bd2a pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Byte[], Boolean)
00000000123d69b0 000007fe9ab33e35 pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Byte[], Int64, Int64, Boolean)
00000000123d6aa0 000007fe9ab3be52 pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Int32, Int32)
00000000123d6b10 000007fe9ab3bd2a pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Byte[], Boolean)
00000000123d6b70 000007fe9ab33e35 pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Byte[], Int64, Int64, Boolean)
00000000123d6c60 000007fe9ab3be52 pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Int32, Int32)
00000000123d6cd0 000007fe9ab3bd2a pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Byte[], Boolean)
00000000123d6d30 000007fe9ab33e35 pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Byte[], Int64, Int64, Boolean)
00000000123d6e20 000007fe9ab3be52 pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Int32, Int32)
00000000123d6e90 000007fe9ab3bd2a pdfrender4net_symbol01.pdfrender4net_symbol09.pdfrender4net_symbol00(Byte[], Boolean)
....
000000001244db60 000007fe9ab31f0e xxx.PDFFile.pdfrender4net_symbol00(System.String, System.IO.Stream, Byte[])
000000001244dbc0 000007fe9ab318e5 xxx.xxx.ConvertPDFToImages(System.IO.Stream, Int32, Int32, System.Drawing.Imaging.ImageFormat, Int32)复制

从卦中信息看,是代码用 ConvertPDFToImages 调用了一个第三方库,在这个库中出现了死递归。

按理说不管外界给了什么参数下去,都不应该用死递归的方式来呈现,所以这类问题可以归于 SDK 的bug,接下来我们的研究方向就是看下这个 SDK 是何方神圣?

[assembly: AssemblyCopyright(" 2008 O2 Solutions")]
[assembly: AssemblyProduct("PDFRender4NET")]
[assembly: AssemblyCompany("O2 Solutions (http://www.o2sol.com/)")]
[assembly: AssemblyTrademark("PDFRender4NET is a trademark of O2 Solutions")]
[assembly: AllowPartiallyTrustedCallers]
[assembly: AssemblyTitle("Print and convert PDF files to images.")]
[assembly: RuntimeCompatibility(WrapNonExceptionThrows = true)]
[assembly: AssemblyDescription("Component for rendering pdf files on .NET platform")]
[assembly: AssemblyConfiguration("")]
[assembly: AssemblyInformationalVersion("2.0.1")]
[assembly: AssemblyKeyName("")]
[assembly: AssemblyDelaySign(false)]
[assembly: CompilationRelaxations(8)]
[assembly: AssemblyVersion("2.0.1.0")]复制

从卦中看还是 2008 年写的 2.0.1 版本,而官网早已出了 2023 年版本,也就是说 15年都没有更新,也是厉害,截图如下:

到这里就可以给到朋友答案了,让他看下能否把 PDFRender4NET 升级到最新版本,按理说应该就没有问题了。

2. 为什么会栈溢出

心细的朋友可能会有一个疑问,既然都栈溢出了,按理说异常码应该是 c0000005 (访问违例),怎么会是 c00000fd 呢?

这是一个非常好的问题,要理解为什么是 c00000fd 而不是 c0000005,需要你对栈的布局有一个比较清晰的理解,为了方便讲述,以当前的 w3wp 来绘制一张图。

画完这张图肯定有朋友会提几个反对意见:

1) 线程栈不是 1M 吗? 怎么会是 512k 呢?

这里要说的是 1M 并不是什么公理,可以在 PE 头上随便设定的,截图如下:

2)PAGE_GUARD 不是 1个内存页吗?

很多教科书都是按 1个内存页 讲述的,但这也不是定死的,也可能是多个内存页,比如 2个,5个,要想验证很简单,用 !address -f:Stack 观察下便知。

0:121> !address -f:Stack

        BaseAddress      EndAddress+1        RegionSize     Type       State                 Protect             Usage
--------------------------------------------------------------------------------------------------------------------------
       0`001f0000        0`00266000        0`00076000 MEM_PRIVATE MEM_RESERVE                                    Stack      [~0; 9e4.e30]
       0`00266000        0`00268000        0`00002000 MEM_PRIVATE MEM_COMMIT  PAGE_READWRITE | PAGE_GUARD        Stack      [~0; 9e4.e30]
       0`00268000        0`00270000        0`00008000 MEM_PRIVATE MEM_COMMIT  PAGE_READWRITE                     Stack      [~0; 9e4.e30]
       ...
       0`15710000        0`15788000        0`00078000 MEM_PRIVATE MEM_RESERVE                                    Stack      [~139; 9e4.14ac]
       0`15788000        0`1578d000        0`00005000 MEM_PRIVATE MEM_COMMIT  PAGE_READWRITE | PAGE_GUARD        Stack      [~139; 9e4.14ac]
       0`1578d000        0`15790000        0`00003000 MEM_PRIVATE MEM_COMMIT  PAGE_READWRITE                     Stack      [~139; 9e4.14ac]复制

接下来我们聊一下什么是 PAGE_GUARD,从名字上看就是 哨兵页,说白一点就是 Windows 做 栈伸展 的一种系统机制,当 rsp 访问到这个区域时会引发系统的 页中断 进而 COMMIT 更多内存页,新的 Commit 页会被 哨兵 侵占,同时也会让渡 RSP 所占的内存页给程序使用,这是一种良性机制,一旦 哨兵 无法侵占更多新的 COMMIT 页时,也就表示栈空间已经到位了,这时候会将自身的 PAGE_GUARD 标签去掉,表示它的使命已完成,如果此时 RSP 访问到了这个弥留的 哨兵区 ,就会抛出 c00000fd 异常,这种异常只是表示 RSP 进入了 哨兵区,不代表栈空间 真的用完了,所以这就是不抛 c0000005 的真正原因,画个简图如下:

说了这么说,如何去验证呢?非常简单,我们提取出 StackLimit, StackBase, RSP 即可。

0:028> r rsp
rsp=00000000123d5fb0

0:028> !teb
TEB at 000007fffff70000
    ExceptionList:        0000000000000000
    StackBase:            0000000012450000
    StackLimit:           00000000123d1000

0:028> !address -f:Stack

        BaseAddress      EndAddress+1        RegionSize     Type       State                 Protect             Usage
--------------------------------------------------------------------------------------------------------------------------
       0`123d0000        0`123d1000        0`00001000 MEM_PRIVATE MEM_RESERVE                                    Stack      [~28; 9e4.bc4]
       0`123d1000        0`12450000        0`0007f000 MEM_PRIVATE MEM_COMMIT  PAGE_READWRITE                     Stack      [~28; 9e4.bc4]复制

从卦中看,当前 哨兵区 = StackLimit ~ StackLimit+0x5000 = 00000000123d1000 ~ 00000000123d6000,然后看下 rsp=00000000123d5fb0 果然是在这个范围内,在一些低级语言中还可以继续放任 栈溢出 异常,继续让程序跑,当代码跑到图中的 MEM_RESERVE 区时这就是货真价实的 c0000005 访问违例。

这次崩溃事故主要还是第三方的SDK代码不健壮导致的 死递归 拖累程序崩溃,解决办法很简单,升级升级再升级,如果还有问题建议提交官方或者使用其他替代品,如果官方解决问题不活跃,你还敢用吗?

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